Chemistry II

How much of solid potassium chromate whould you use to prepare 2.00 L of 0.400 M potassium chromate?

M x L = mols
g/molar mass = mols OR
M x L = g/molar mass
solve for g.

.400 mol/L x 2.00 = g/194
g = 155.2

Thanks!!

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asked by Jayd

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