1)Write an equation in the slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation
(2,-2), y=-x-2.
A) y=-2x
B) y=2x
C) y=1/2x
D) y=-x
I do not know how to solve these.
I don't need help anymore.
Since the new line is to be parallel to the given one y = -x - 2
it will differ only in the constant at the end.
let the new one be y = -x + b
sub in the point (2, -2) and you will find the value of b
Give it a try, let me know what you got
To find the equation of a line parallel to the given equation, we need to determine the slope of the given line. The slope-intercept form of a line is given by y = mx + b, where m is the slope and b is the y-intercept.
The given equation is y = -x - 2. Comparing this equation to the slope-intercept form, we can see that the slope (m) of the line is -1.
Since a line parallel to the given line will have the same slope, the equation for the line passing through the given point (2, -2) can be written as y = -1x + b. To determine the value of b, we substitute the x and y values of the given point into this equation:
-2 = -1(2) + b
-2 = -2 + b
b = 0
So the equation of the line passing through the given point (2, -2) and parallel to the given equation y = -x - 2 can be written as y = -x + 0, which simplifies to y = -x.
Therefore, the correct answer is D) y = -x.