math.

Abel ,Belle and Cindy have $408 altogether. Belle has $7 more than Cindy And $5 more than Abel. how much does Abel have?

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asked by charlie
  1. A + B + C = 408

    B = C + 7 = A + 5 ... A = B - 5 ... C = B - 7

    solve by substitution

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    posted by R_scott
  2. Cindy has $X.
    Belle has $(X+7).
    Abel has $(X+7)-5.

    x + (x+7) + (x+7)-5 = 408.
    3x = 399,
    X = 133.
    Abel amt. = (x+7)-5 = (133 + 7)- 5 = $135.

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    posted by Henry2
  3. Thank you for your quick response. It is very clear.
    Charlie

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    posted by charlie
  4. Glad I could help.

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    posted by Henry2

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