# math.

Abel ,Belle and Cindy have \$408 altogether. Belle has \$7 more than Cindy And \$5 more than Abel. how much does Abel have?

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1. A + B + C = 408

B = C + 7 = A + 5 ... A = B - 5 ... C = B - 7

solve by substitution

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posted by R_scott
2. Cindy has \$X.
Belle has \$(X+7).
Abel has \$(X+7)-5.

x + (x+7) + (x+7)-5 = 408.
3x = 399,
X = 133.
Abel amt. = (x+7)-5 = (133 + 7)- 5 = \$135.

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posted by Henry2
3. Thank you for your quick response. It is very clear.
Charlie

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posted by charlie
4. Glad I could help.

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posted by Henry2

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