Find the domain of the function.
f(s)= sqrt s-1 over s-4
I think I have to solve the inequality (s-1)>=0 but I do not know how to.
what are the conditions for the function to have a real value?
to have the numerator of √(s-1) to be real, s-1 must be ≥ 0, so s ≥ 1 (I just added 1 to both sides)
secondly, we cannot divide by zero.
When does that happen??
What if s = 4 in (s-4) ??
I see trouble!