Math

Combine the following rational expressions
1/2y-5-30/8y^3-125
Lcm:(2y-5)(4y^2+10y+125)
=1*4y^2+10y+25/(2y-5)(4y^2+10y+25)-30/(2y-5)(4y^2+10y+25)
=4y^2-10y+25-30/(2y-5)(4y^2+10y+25)

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1. 1/(2y-5) - 30/(8y^3-125)
1/(2y-5) - 30/((2y)^3 - 5^3)
1/(2y-5) - 30/((2y-5)(4y^2+10y+25))
The LCM is just (8y^3-125), so that gives

((4y^2+10y+25)-30)/(8y^3-125) = (4y^2+10y-5)/(8y^3-125)

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posted by Steve

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posted by Steve

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