What is the concentration of a potassium iodate solution after you complete the following porcedure? Pipette 10 mL of a 0.31 M potassium iodate stock solution to a 100-mL volumetric flask and then add water to the mark.
To calculate the concentration of the potassium iodate solution after the given procedure, we need to use the concept of dilution.
Step 1: Calculate the moles of potassium iodate in the stock solution.
To find the moles of potassium iodate, we use the formula:
moles = concentration (M) × volume (L)
Given that the volume is 10 mL and the concentration is 0.31 M, we can calculate the moles as follows:
moles of potassium iodate = 0.31 M × 0.01 L = 0.0031 mol
Step 2: Calculate the final volume of the diluted solution.
The final volume is given as 100 mL, which is equivalent to 0.1 L.
Step 3: Calculate the concentration of the diluted solution.
To find the concentration, we divide the moles by the final volume:
concentration (M) = moles / volume (L)
concentration (M) = 0.0031 mol / 0.1 L = 0.031 M
Therefore, the concentration of the potassium iodate solution after the given procedure is 0.031 M.
The new concentration will be a tenth of the original concentration
0.31M*(1/10)=????