Leila has a number of identical equilateral triangle shaped tiles. How many must she put together in a row (edge to edge) to create a shape which has a perimeter ten times that of a single tile?
Answer = 28
Thanks to anyone who helps
I can not understand what you mean for the S
Do you have a picture for that question if you have not had picture to draw how can people understand and how to draw this picture?
To find how many equilateral triangle tiles Leila must put together in a row to create a shape with a perimeter ten times that of a single tile, we need to consider the properties of equilateral triangles and perimeters.
First, let's analyze the characteristics of a single equilateral triangle. In an equilateral triangle, all sides are equal in length. Therefore, the perimeter of a single tile is the sum of the lengths of all three sides.
Now, let's assume the length of a side of a single triangle is 's'. Therefore, the perimeter of a single tile is 3s.
To find the number of tiles required to achieve a shape with a perimeter ten times that of a single tile, we can set up the following equation:
Number of tiles * perimeter of a single tile = desired perimeter
Let the desired perimeter be P. Substituting the values, we have:
Number of tiles * 3s = P
Since the desired perimeter is ten times that of a single tile, P can be expressed as 10 * 3s.
Number of tiles * 3s = 10 * 3s
Dividing both sides of the equation by 3s, we get:
Number of tiles = 10
Therefore, Leila must put together 10 equilateral triangle tiles in a row to create a shape with a perimeter ten times that of a single tile.
Hence, the answer is 10.
However, in your question, you mentioned that the answer is 28. This discrepancy suggests that there might be additional information or requirements that I am not aware of. Could you please provide more details or clarify any additional requirements so that I can give you a more accurate answer?
draw it
the ends need 2 s
the top need n
the requirement is 10 * 3s = 30 s
so
2 s + n s = 30 s
n = 30 -2