What is the approximate distance between the pair of points (5,4) and (14,16)? Please help ASAP!!!! :( I only know that the exact distance between the pair of points (5,4) and (14,16) is 15 units!!!
okay ... exact will do for approximate
sometimes when something is approximated , you hit it right on the nose
(5,4), (14,16).
X = 14 - 5 = 9.
Y = 16 - 4 = 12.
d^2 = x^2 + y^2 = 9^2 + 12^2 = 225,
d = 15 units.
To find the approximate distance between the pair of points (5,4) and (14,16), you can use the distance formula, which is derived from the Pythagorean theorem. The distance formula is given by:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case, (x1, y1) = (5,4) and (x2, y2) = (14,16).
Plugging the values into the formula:
d = sqrt((14 - 5)^2 + (16 - 4)^2)
= sqrt(9^2 + 12^2)
= sqrt(81 + 144)
= sqrt(225)
= 15 units
So the approximate distance is indeed 15 units, as you mentioned.
To find the approximate distance between the points (5,4) and (14,16), we can use the distance formula. The distance formula is given by:
d = √((x2 - x1)^2 + (y2 - y1)^2)
where (x1, y1) and (x2, y2) are the coordinates of the two points.
In this case, (x1, y1) = (5,4) and (x2, y2) = (14,16). Substituting these values into the formula, we have:
d = √((14 - 5)^2 + (16 - 4)^2)
Simplifying further:
d = √(9^2 + 12^2)
d = √(81 + 144)
d = √225
d = 15
So the approximate distance between the points (5,4) and (14,16) is also 15 units.