# Maths

solve in simultaneous method
a+2b=13
2a-3b=5

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1. a+2b=13 ... multiplying by 2 ... 2 a + 4 b = 26

2a-3b=5

subtracting equations (to eliminate a) ... 7 b = 21

solve for b , then substitute back to find a

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2. A+2B=13 2A-3B=5

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3. Solve the equations a+2b=13, 2a-3b = 5 using two methods

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4. I don't understand

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5. Semultanios

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