# Math

The 3rd and 9th term of a g.p are 54 and 39,336 respectively.find the 6th term,sum of 4th term,sum of 4th and 7th term and product of 2nd and 5th term

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1. there are 6 terms between 54 and 39336, so
r^6 = 39336/54 = 6556/9
I suspect a typo, since it is not rational.
Anyway, use that or fix it, and you will have r.
Then a = 54/r^2

Having a and r, you can find any other terms.
"sum of 4th term" makes no sense.

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posted by Just math
2. "3rd and 9th term of a g.p are 54 and 39,336"
--> ar^2 = 54 and ar^8 = 39336
ar^8/(ar^2) = 39336/54
r^6 = 728.444.. , I suspect that was supposed to be 729 , since 3^6 = 729

I will go with r = ± 3
then in ar^2 = 54
9a = 54 , ----> a = 6

so your typo was in 9th term is 39366 instead of your 39336

take the rest from there

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posted by Reiny

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