Which equation has (2, -1) as a solution?

Y = 2x - 1
Y = x + 3
Y = x - 3
Y = -2x + 1

Plug in (2, -1) into each equation to see which equations yield true.

Is it d?

No.

Sorry I'm just dumb... It's b dont know how I couldn't figure that out for about 10 mins but I got it now lol thx

To find out which equation has (2, -1) as a solution, we need to substitute the coordinates (2, -1) into each equation and see which equation satisfies the coordinates.

Let's start with the first equation:

Y = 2x - 1

Substituting x = 2 and y = -1:

-1 = 2(2) - 1
-1 = 4 - 1
-1 = 3

Since -1 does not equal 3, the first equation does not satisfy the coordinates (2, -1).

Now let's move on to the second equation:

Y = x + 3

Substituting x = 2 and y = -1:

-1 = 2 + 3
-1 = 5

Again, -1 does not equal 5, so the second equation does not satisfy the coordinates.

Let's check the third equation:

Y = x - 3

Substituting x = 2 and y = -1:

-1 = 2 - 3
-1 = -1

This time, -1 equals -1, so the third equation satisfies the coordinates (2, -1).

Lastly, let's try the fourth equation:

Y = -2x + 1

Substituting x = 2 and y = -1:

-1 = -2(2) + 1
-1 = -4 + 1
-1 = -3

Once again, -1 does not equal -3, so the fourth equation does not satisfy the coordinates.

Therefore, the equation that has (2, -1) as a solution is:

Y = x - 3.