3 12 21 30 find the 1000th term of this sequence

keep adding 9. That is,

a=3,d=9
T1000 = a+999d = ?

To find the 1000th term of the sequence 3, 12, 21, 30, we need to determine the pattern of the sequence and use it to calculate the desired term.

Looking at the given sequence, we can observe that each term is obtained by adding 9 to the previous term.

So, we can write the general formula for the nth term as:

nth term = first term + (n - 1) * common difference

In this case, the first term is 3, and the common difference is 9.

Therefore, the formula for the nth term becomes:

nth term = 3 + (n - 1) * 9

Now we can substitute n = 1000 and calculate the 1000th term:

1000th term = 3 + (1000 - 1) * 9
= 3 + 999 * 9
= 3 + 8991
= 8994

So, the 1000th term of the sequence is 8994.

To find the 1000th term of the given sequence, we need to determine the pattern or formula that generates the terms. Looking at the sequence, we can observe that each term is obtained by adding 9 to the previous term.

So, let's break down the sequence:

3, 12, 21, 30, ...

To obtain the next term, we add 9 to the previous term:

3 + 9 = 12
12 + 9 = 21
21 + 9 = 30
...

Since the pattern is consistent, we can express the nth term of the sequence as:

a_n = a_1 + (n-1)d

where a_n is the nth term, a_1 is the first term, and d is the common difference between consecutive terms.

In this case, the first term (a_1) is 3, and the common difference (d) is 9. Plugging these values into the formula, we have:

a_n = 3 + (n-1)9

To find the 1000th term, we substitute n = 1000 into the formula:

a_1000 = 3 + (1000-1)9

Simplifying further:

a_1000 = 3 + 999(9)
a_1000 = 3 + 8991
a_1000 = 8994

Therefore, the 1000th term of the sequence is 8994.