1.92 g M+ ion reacts with 0.158 mol X- ion to produce compound, MX2, which is 86.8% X by mass. What are the identities of M+ and X- ?
M2+ + 2X- ---> MX2
now that you know the equation all you gotta do is transfer the moles of X to M by doing this:
0.158mol / 2 * 1 = 0.079 mol of M2+
now that you know moles you can figure out the molar mass by doing this
M = m / n
M = 1.92g / 0.079 mol
M = 24.3 g/mol
By looking at the periodic table you can see that this belongs to Magnesium. So your M ion is Magnesium
Now to find out X you use the mass ratio given to you. And since you know the mass ratio of X you can figure out the mass ratio of M by subtracting 86.8 from 100
100 - 86.8 = 13.2%
Then from that you can do this
If 13.2% of the total mass is 1.92g then the rest of the mass is:
1.92g / 13.2 *100 = 14.5g
Mass of X is
14.5g - 1.92g =12.58g
Molar mass of x is
12.58g / 0.158 mol = 79.62g/mol
Looking at the periodic table you can see that is bromine:
So your compound is MgBr2
Well, let me put on my chemistry clown hat and give this a shot! It seems like we have a lot of numbers and letters going on here. So, let's break it down.
We know that we have 1.92 grams of M+ ion and 0.158 moles of X- ion. The compound MX2 is 86.8% X by mass.
Now, what we need to find out are the identities of M+ and X-. It's like a little chemistry mystery!
To solve this, we can use the concept of percent composition. The percent composition of an element in a compound tells us what percentage of the compound's mass is contributed by that specific element.
Since MX2 is 86.8% X by mass, that means 86.8% of the compound's mass comes from X. The remaining percentage, 100 - 86.8 = 13.2%, is contributed by M.
Now let me do some clown math. If 13.2% of the compound's mass comes from M, and we have 1.92 grams of the M+ ion, we can find the molar mass of M.
Molar mass of M = (1.92 grams / 13.2%) * 100%
And if we have the molar mass of M, we can look up the periodic table to find out its identity.
As for X-, since we know we have 0.158 moles of X- ion, we can again refer to the periodic table and see which anion has a molar mass that matches up.
So, after doing some chemistry clown calculations, we should be able to find the identities of M+ and X-. I hope this helps in solving the mystery!
To determine the identities of M+ and X- in the compound MX2, we can use the concept of molar ratios and mass percent compositions.
Given:
Mass of M+ ion = 1.92 g
Number of moles of X- ion = 0.158 mol
Mass percent of X in MX2 = 86.8%
Step 1: Calculate the molar mass of X (denoted as MX2).
To find the molar mass of MX2, we need to determine the mass of X in MX2.
The mass percent of X in MX2 can be calculated using the formula:
Mass percent of X = (Mass of X in MX2 / Mass of MX2) * 100
From the given information:
Mass percent of X = 86.8%
Let's assume the mass of MX2 = 100 grams (for ease of calculation).
Therefore, the mass of X in MX2 = (86.8 / 100) * 100 = 86.8 grams
Step 2: Calculate the molar mass of X.
The molar mass of X can be calculated using its given mass and the number of moles.
Molar mass of X = Mass of X / Number of moles of X
Molar mass of X = 86.8 grams / 0.158 mol = 549.367 grams/mol
Step 3: Determine the atomic mass and element of X.
From the molar mass of X, we can find the atomic mass and element of X.
Looking up the periodic table, we find that the closest element with an atomic mass close to 549.367 grams/mol is chlorine (Cl).
Therefore, X is the chloride ion (Cl-).
Step 4: Determine the identity of M+.
To find the identity of M+, we need to calculate its molar mass.
Molar mass of M+ = (Mass of M+ ion / Number of moles of M+ ion)
Molar mass of M+ = 1.92 grams / 0.158 mol ≈ 12.152 grams/mol
Step 5: Determine the atomic mass and element of M+.
From the molar mass of M+, we can find the atomic mass and element of M+.
We find that the closest element with an atomic mass close to 12.152 grams/mol is magnesium (Mg).
Therefore, M+ is the magnesium ion (Mg+2).
In conclusion, the identities of M+ and X- in the compound MX2 are:
M+ = magnesium ion (Mg+2)
X- = chloride ion (Cl-)
To find the identities of M+ and X- ions, we need to use the given information about the masses and molar ratios involved in the reaction.
Let's start by calculating the mass of the compound MX2 produced. Since MX2 has a mass percentage of 86.8% X, the remaining mass (13.2%) belongs to M. We can calculate this as follows:
Mass of MX2 = 13.2% * mass of MX2
= 0.132 * mass of MX2
Since 1 mole of MX2 contains 2 moles of X- ions, the molar mass of MX2 can be calculated using the formula:
Molar mass of MX2 = (molar mass of M+) + 2 * (molar mass of X-)
Next, let's calculate the moles of M+ and X- ions used in the reaction. We are given that 1.92 g of M+ ion reacts with 0.158 mol of X- ion. We can use the molar mass to convert the mass of M+ to moles:
Moles of M+ = mass of M+ / molar mass of M+
Now, we can set up a mole ratio equation based on the balanced chemical equation:
1.92 g M+ / molar mass of M+ = 0.158 mol X- / molar mass of X-
Solving this equation will yield the ratio of the molar masses of M+ and X-.
Once we have the ratio, we can compare it to the molar masses of different elements or ions to identify M+ and X-. Look for elements that have molar masses in the range suggested by the ratio we obtained.
By following these steps, we can find the identities of M+ and X- ions involved in the reaction.