a truck travels beneath an airplane that is moving 120 km/ hr at an angle if 49 degrees to the ground. how fast must the truck travel to stay beneath the airplane. answer in u its of km/h
120 cos 49 is component of airplane velocity parallel to ground.
To find out how fast the truck must travel to stay beneath the airplane, we need to break down the velocity of the airplane into its horizontal and vertical components.
The horizontal component of the airplane's velocity can be found by multiplying its speed (120 km/hr) by the cosine of the angle of 49 degrees: cos(49).
Horizontal component = 120 km/hr * cos(49)
Next, we can equate the horizontal component of the airplane's velocity to the truck's velocity to determine the speed required:
Truck's velocity = 120 km/hr * cos(49)
Calculating the value:
Truck's velocity = 120 km/hr * cos(49)
Truck's velocity = 120 km/hr * 0.6494
Truck's velocity ≈ 77.93 km/hr
Therefore, the truck must travel at approximately 77.93 km/hr to stay beneath the airplane.