two numbers are in the ratio of 7:9.the larger number is 54.find the smaller number.
S = smaller number.
L = larger number = 54
S / L = 7 / 9
S / 54 = 7 / 9
Cross multiply:
9 ∙ S = 54 ∙ 7
9 S = 378
Divide both sides by 9
S = 378 / 9
S = 42
Proof:
42 / 54 = 6 ∙ 7 / 6 ∙9 = 7 / 9
since 54 = 9*6,
7:9 = 7*6:9*6 = 42:54
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7/9
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Two numbers are in the ratio of 7:9 the larger number is 54 find the smaller number
Let's assume the smaller number as x.
According to the given condition, the ratio of two numbers is 7:9.
Hence, x/54 = 7/9
Cross multiplying the equation, we get:
9x = 54 * 7
Solving the above equation, we get:
x = 378/9 = 42
Hence, the smaller number is 42.