The equation of a simulated photosynthesis reaction is represented by 6CO2(g) + 6H2O (g) -> C6H12O6(s) + 6O2(g) At 31 degree celcius, tje following equilibrium concentration were found [H2O] = 7.91X10^-2M [CO2]= 9.30X10^-1M [O2]= 2.40X10^-3M Determine the initial mass of CO2 involved in the above reaction
Thank you Dr, i have did the same method as you ๐. But i only managed to get the concentration of CO2 , instead of mass of CO2. Do you think the question lack of information if we are required to find mass of CO2?
I would do it this way with y = initial concentration of CO2 and z the initial concentration of H2O
..............................6CO2(g) + 6H2O (g) -> C6H12O6(s) + 6O2(g)
I................................y.................z..................solid.................0
C.............................-6x............-6x..................solid...............+6x
E............................y-6x...........z-6x................solid................+6x
Now you know y-6x = 0.930 M and 6x = 0.0024 M
Solve for y
To determine the initial mass of CO2 involved in the reaction, we need to use the given equilibrium concentrations of the reactants and the ideal gas law equation. However, we first need to convert the concentration of CO2 to moles per liter (mol/L) before we can proceed.
The molar mass of CO2 is 44.01 g/mol. Let's calculate the moles of CO2 using the given concentration:
[CO2] = 9.30 ร 10^(-1) M
Moles of CO2 = concentration (mol/L) ร volume (L)
Since the volume is not provided, we assume it to be 1 L.
Moles of CO2 = 9.30 ร 10^(-1) mol/L ร 1 L
Now, we can calculate the initial mass of CO2 using the moles and molar mass:
Initial mass of CO2 = moles of CO2 ร molar mass of CO2
Initial mass of CO2 = (9.30 ร 10^(-1) mol) ร (44.01 g/mol)
Finally, perform the calculation to find the initial mass of CO2.
Note: The given temperature (31ยฐC) is not needed for this calculation.
Initial mass of CO2 = 9.30 ร 10^(-1) ร 44.01
The product of this expression will give you the initial mass of CO2 involved in the reaction.