geometry
 👍
 👎
 👁

 👍
 👎

 👍
 👎

 👍
 👎

 👍
 👎
Respond to this Question
Similar Questions

Geometry
For the acute angles in a right triangle, sin (4x)° = cos (3x + 13) °. What is the number of degrees in the measure of the smaller angle

calculus
Find complete length of curve r=a sin^3(theta/3). I have gone thus (theta written as t) r^2= a^2 sin^6 t/3 and (dr/dt)^2=a^2 sin^4(t/3)cos^2(t/3) s=Int Sqrt[a^2 sin^6 t/3+a^2 sin^4(t/3)cos^2(t/3)]dt =a Int

Math
If A and B are acute angle such that SinA=8/17 and CosB=3/5.Find 1, Cos(A+B) 2, Sin(A+B) 3, Sin(AB)

Trig
Find sin(s+t) and (st) if cos(s)= 1/5 and sin(t) = 3/5 and s and t are in quadrant 1. =Sin(s)cos(t) + Cos(s)Sin(t) =Sin(1/5)Cos(3/5) + Cos(1/5)Sin(3/5) = 0.389418 Sin(st) =sin(s)cos(t)  cos(s)sin(t) =sin(3/5)cos(1/5) 

Trig
A. Find simpler, equivalent expressions for the following. Justify your answers. (a) sin(180 + è) (b) cos(180 + è) (c) tan(180 + è) B. Show that there are at least two ways to calculate the angle formed by the vectors [cos 19,

Calculus 12th grade (double check my work please)
1.)Find dy/dx when y= Ln (sinh 2x) my answer >> 2coth 2x. 2.)Find dy/dx when sinh 3y=cos 2x A.2 sin 2x B.2 sin 2x / sinh 3y C.2/3tan (2x/3y) D.2sin2x / 3 cosh 3yz...>> my answer. 2).Find the derivative of y=cos(x^2) with

Math
1. Write the expression as a function of an acute angle whose measure is less than 45. a. sin 80 b. sin (100) To find the postive acute angle, usually you would subtract 360 from the given measure. Would you have to subtract 45

Math Help Please
What are the ratios for sin A and cos A? The diagram is not drawn to scale. Triangle Description AB = 29 AC = 20 BC  21 A. sin A = 20/29, cos A = 21/29 B. sin A = 21/29, cos A = 20/21 C. sin A = 21/29, cos A = 20/29****? D. sin

math
Can you please check my work. A particle is moving with the given data. Find the position of the particle. a(t) = cos(t) + sin(t) s(0) = 2 v(0) = 6 a(t) = cos(t) + sin(t) v(t) = sin(t)  cos(t) + C s(t) = cos(t)  sin(t) + Cx + D

calculus
Find the points on the curve y= (cos x)/(2 + sin x) at which the tangent is horizontal. I am not sure, but would I find the derivative first: y'= [(2 + sin x)(sin x)  (cos x)(cos x)]/(2 + sin x)^2 But then I don't know what to

Calculus
Find the velocity, v(t), for an object moving along the xaxis in the acceleration, a(t), is a(t)=cos(t)sin(t) and v(0)=3 a) v(t)=sin(t) + cos(t) +3 b) v(t)=sin(t) + cos(t) +2 c) v(t)= sin(t)  cos(t) +3 d) v(t)= sin(t)  cos(t)

trig
The expression 4 sin x cos x is equivalent to which of the following? (Note: sin (x+y) = sin x cos y + cos x sin y) F. 2 sin 2x G. 2 cos 2x H. 2 sin 4x J. 8 sin 2x K. 8 cos 2x Can someone please explain how to do this problem to
You can view more similar questions or ask a new question.