Find the measure of the acute angle x, if :
sin(x)=0.0175; sin(x)=0.5015; cos(x)=0.06814; cos(x)=0.0670.
I know that Sin(x)=opp./hyp. and that cos(x)=adj./hyp. but i have no clue about how to find the xs in these equations
I just did all the problems in the packets and when i turned them in the were wrong, i did sin^-1=0.5015; cos^-1=0.06814; cos^-1=0.067 to find x is that what i'm supposed to do?
I also got them wrong until I put the degree sign on my homework, so don't forget the degree sign.
Well, if you have no clue, maybe you should "angle" yourself towards some "acute" humor to lighten the mood! 🤡
Okay, let's break it down. Since sin(x) = opp./hyp., we can use the arcsin function to find the angle x.
For sin(x) = 0.0175:
x = arcsin(0.0175) ≈ 1 degree
For sin(x) = 0.5015:
x = arcsin(0.5015) ≈ 30 degrees
Now, let's move on to cos(x) = adj./hyp.
For cos(x) = 0.06814:
x = arccos(0.06814) ≈ 88.5 degrees
And for cos(x) = 0.0670:
x = arccos(0.0670) ≈ 88.6 degrees
So there you have it! The measure of the acute angle x approximately comes out to be 1 degree, 30 degrees, 88.5 degrees, and 88.6 degrees respectively. Just remember, angles can be "sin-fully" funny sometimes! 😄🤡
To find the measure of the acute angle x using trigonometric functions, you need to use inverse trigonometric functions. In this case, you need to use the inverse sine (sin^(-1)) and inverse cosine (cos^(-1)) functions.
Let's go through each given equation one by one:
1. sin(x) = 0.0175:
To find x, you can use the inverse sine function. Take the inverse sine (sin^(-1)) of both sides of the equation:
x = sin^(-1)(0.0175)
2. sin(x) = 0.5015:
Similarly, use the inverse sine function:
x = sin^(-1)(0.5015)
3. cos(x) = 0.06814:
To find x in this equation, you need to use the inverse cosine function. Take the inverse cosine (cos^(-1)) of both sides:
x = cos^(-1)(0.06814)
4. cos(x) = 0.0670:
Again, use the inverse cosine function:
x = cos^(-1)(0.0670)
By plugging these equations into a calculator or using a math software, you can find the values of x for each given equation. Keep in mind that these inverse trigonometric functions give the principal value within a certain range, usually between -π/2 and π/2 or 0 and π, depending on the software or context.
thank you so much!
your calculator has a 2nd function button of some kind, which makes
sin into sin^-1
so, if sin(x) = 0.0175, x = sin^-1(0.0175) = 1.00°
so, reread this section of your text, and the user guide for your calculator.