Suppose a normal distribution has a mean of 20 and a standard deviation of 4.
What is the z-score value 0.52. Its standard deviations is less than the mean?
-0.13
0.13
help please
z-score= (given value - mean)/sd
.52 = (given value - 20)/4
solve for "given value" , let me know what you get, and I will verify.
To find the z-score value, you need to use the formula:
Z = (X - μ) / σ
Where:
Z is the z-score,
X is the value you want to convert,
μ is the mean of the distribution,
σ is the standard deviation of the distribution.
In this case, you have the following values:
X = 0.52
μ = 20
σ = 4
Plug in these values into the formula:
Z = (0.52 - 20) / 4
Perform the calculation:
Z = -19.48 / 4
Z ≈ -4.87
So, the z-score value for 0.52, where its standard deviation is less than the mean, is approximately -4.87.
However, it seems like you made a mistake in your question. There is no z-score value of 0.52 with a standard deviation less than the mean. Please check your calculations or provide the correct value, and I will be happy to help.