My 3 digit number has 4 in the hundreds place.It has a greater digit in the tens place than in ones place.The sum of the digits is 6.What is my number?

4 _ _

420

4+5+3

Thanks guys

To find the number, let's consider the given clues step by step:

1. The number has 4 in the hundreds place: Since it is a 3-digit number, we know that the hundreds place must be occupied by the digit 4.

2. The tens place digit is greater than the ones place digit: Since the only digits left are 0, 1, 2, 3, 5, 6, 7, 8, and 9, we can start by checking the possible options for the tens and ones place that satisfy this condition.

We can exclude the digits 5, 6, 7, 8, and 9 as they are greater than 4. So, the possible digits for the tens place are 0, 1, 2, and 3. This means that the possible digits for the ones place are 0, 1, 2, 3.

3. The sum of the digits is 6: We need to find the combination of digits that add up to 6. By testing different options, we can see that 4 + 1 + 1 equals 6.

Therefore, the number that satisfies all the given conditions is 411.