Calculate how much heat is required to bring 157 g of water from a temperature of 89.8°C to a temperature of 100°C. The specific heat of water is 4186 J/kg∙°C.
m*c*deltaTemp, you can do that. Watch units, you have to convert grams.
To calculate the heat required to raise the temperature of the water, we can use the formula:
Q = m * c * ΔT
Where:
Q = heat energy
m = mass of the substance (in kg)
c = specific heat capacity of the substance (in J/kg∙°C)
ΔT = change in temperature (in °C)
First, let's convert the mass of water from grams to kilograms:
mass = 157 g * (1 kg / 1000 g)
mass = 0.157 kg
Now we can calculate the heat energy:
Q = 0.157 kg * 4186 J/kg∙°C * (100°C - 89.8°C)
Q = 0.157 kg * 4186 J/kg∙°C * 10.2°C
Q ≈ 6792 J
Therefore, approximately 6792 Joules of heat energy is required to bring 157 g of water from a temperature of 89.8°C to a temperature of 100°C.