1. The image shows a man pulling a truck. If it does not show up for you for whatever reason, this is a description of the image.
Assume it takes 2500 N for him to pull the truck along the road at a constant speed.
a. Find the net force acting on the truck.
b. Find the force of friction acting on the truck.
2. Find the acceleration of a 10 N on a 10kg mass. How does it compare to the acceleration if you double the force on an object that is double the mass? Support your answer with work.
3. How much pressure are you exerting on the ground when you are standing on one foot? (Assume your shoes are rectangular shaped.)
* convert to S.I. Units.
Someone please give me the answers and the work
3. What is your weight on one foot divided by area?
2. F=ma, a=F/m
1. at constant speed, net force has to be zero (net F=m*a)
1. To find the net force acting on the truck, we need to consider the forces acting on it. The only force mentioned in this scenario is the force applied by the man, which is 2500 N. Since the truck is being pulled at a constant speed, we can assume there is no acceleration, meaning the net force is zero. Therefore, the net force acting on the truck is 0 N.
To find the force of friction acting on the truck, we need to use the concept of static friction. When an object is moving at a constant speed, the force of static friction balances the applied force to keep the object moving. In this case, the applied force is 2500 N. Thus, the force of static friction acting on the truck is 2500 N.
2. We can use Newton's second law of motion to find the acceleration of an object. The formula is F = ma, where F is the force acting on the object, m is the mass of the object, and a is the acceleration.
For the given case, the force acting on the 10 kg mass is 10 N. Using Newton's second law, we can rearrange the formula to find the acceleration:
a = F/m
a = 10 N / 10 kg
a = 1 m/s²
Therefore, the acceleration of the 10 kg mass is 1 m/s².
If we double the force on an object that is double the mass, we can apply the same formula to find the new acceleration. Let's assume the original mass is 10 kg and the original force is 10 N.
Force = 2 * 10 N = 20 N
Mass = 2 * 10 kg = 20 kg
Using Newton's second law:
a = F/m
a = 20 N / 20 kg
a = 1 m/s²
As we can see, the acceleration remains the same even when we double both the force and mass of the object.
3. To calculate the pressure exerted on the ground when standing on one foot, we need to know the weight and the area of the foot in contact with the ground.
Let's assume the weight of the person is 600 N and the foot has an area of 0.05 square meters.
Pressure = Force / Area
Using the given values:
Pressure = 600 N / 0.05 m²
Pressure = 12,000 N/m²
Therefore, the pressure exerted on the ground when standing on one foot is 12,000 N/m² or 12,000 Pascal (Pa), which is the SI unit for pressure.