the length of a rectangular playing field is 5ft less than twice its width. If the perimeter is of the playing field is 230ft, find the lenght and width of the field.
How would I even begin to set up the equatin let alone solve the equation
230=2w-5+2w-5+w+w
this is bcus your length being 2w-5. so you add length+length+width+width=per.
then 230=6w-10
240=6w
240/6=w
So your width is 40 and you length is 75
To solve this problem, you can start by setting up the equation based on the given information.
Let's assume the width of the rectangular playing field is 'w' feet.
According to the problem, the length of the field is 5 feet less than twice its width. So, the length would be (2w - 5) feet.
To find the perimeter, we add up the lengths of all four sides:
Perimeter = length + length + width + width
So, the perimeter equation can be written as:
230 = (2w - 5) + (2w - 5) + w + w
Simplifying this equation, we have:
230 = 6w - 10
Now, let's isolate the variable 'w' by bringing all terms with 'w' to one side:
6w - 10 = 230
Next, let's move the constant term to the other side:
6w = 230 + 10
6w = 240
Now, divide both sides of the equation by 6 to solve for 'w':
w = 240 / 6
w = 40
So, the width of the rectangular playing field is 40 feet.
To find the length, substitute the value of 'w' into the length expression:
length = 2w - 5
length = 2(40) - 5
length = 80 - 5
length = 75
Therefore, the length of the rectangular playing field is 75 feet and the width is 40 feet.