Jaime graphed linear data in the form (cost, number). The y-intercept was 0. Jayla graphed the same data in the form (number, cost). What was the y-intercept of her graph? Complete the explanation.

Jaime's graph contained (0,1) (0,0) or (1,0). Since Jayla's data were the same but with the x and y switched her graph also contained (1,0) (0,1) or
(0,0).

I am confused on this and don't know what the proper answer should be. Please help.

In both Jaime's and Jayla's graphs, the y-intercept represents the cost when the number is zero.

From Jaime's graph, we can see that the y-intercept is at (0,0). This means that when the number is zero, the cost is also zero on Jaime's graph.

Since Jayla's data is the same as Jaime's data but with the x and y coordinates switched, we can infer that the y-intercept of Jayla's graph would be when the cost is zero (since that would be the equivalent position to Jaime's y-intercept).

Looking at Jaime's graph, we see that when the number is zero, the cost is also zero. Therefore, the y-intercept of Jayla's graph would be at (0,0). This means that when the cost is zero, the number is also zero on Jayla's graph.

Therefore, the y-intercept of Jayla's graph is (0,0).

To determine the y-intercept of Jayla's graph, we need to understand what the y-intercept represents in a linear equation. In the form (number, cost), the y-intercept is the point where the line intersects the y-axis.

In Jaime's graph, the y-intercept is (0,0), which means that when the number is 0, the cost is also 0.

Since Jayla's data are the same as Jaime's but with the x and y values switched, we can infer that the point (0,0) in Jaime's graph would correspond to the point (0,0) in Jayla's graph, as the x and y values are simply switched. This means that Jayla's graph will also have a y-intercept of 0.

Therefore, the y-intercept of Jayla's graph is 0, just like Jaime's graph.

if the y-intercept is 0, then y=kx

That means its inverse is also of the form y=mx, where m = 1/k

Now the rest should come easy.