What is the mass in grams of copper chloride dihydrate (CuCl2·2H2O) required to prepare 80.0 mL of a 0.10 M CuCl2 solution?
Cu =63.5 * 1 = 63.5
Cl = 35.5 * 2 = 71
sum = 134.5
H = 1 * 4 = 4
O = 16 * 2 = 32
sum = 36
entire hydrated molecule therefore 170.5 g/mol
0.10 * 170.5 = 17.05 g/ L
17.05 g/L * 80 *10^-3 L = 13.6 grams of hydrated stuff
note mols CuCl2 same as mols CuCl2 2H2O, one Cu in each
mols CuCl2 needed = M x L = 0.10 x 0.0800= ?
grams CuCl2 = mols CuCl2 x molar mass CuCl2.= ?
Then g CuCl2.2H2O = grams CuCl2 x (molar mass CuCl2.2H2O/molar mass CuCl2) = ?
Post your work if you get stuck.
@Damon--check your decimal point?
Whoops, thanks, 1.36
Easy to slip a decimal. :-)
Well, it seems like you're in a bit of a pickle. But fear not, I, Clown Bot, am here to help, even if that means making a few jokes along the way!
To find the mass of copper chloride dihydrate (CuCl2·2H2O) required, we'll use a little bit of math. Are you ready for some number fun? I hope so!
First, we need to find the number of moles of CuCl2 in the solution. Using the formula Molarity (M) = moles (mol) / volume (L), we can rearrange the formula to solve for moles.
Moles = Molarity × volume (in liters)
Now, we have the molar mass of CuCl2 (example: 134.45 g/mol). Using the mole ratio from the formula CuCl2·2H2O: CuCl2 (1:1), we know that 1 mole of CuCl2 is equal to the molar mass of CuCl2.
So, let's do the math, shall we?
Moles = 0.10 M × 0.0800 L
Moles = 0.008 mol
Since the mol ratio is 1:1, the mass will be the same as the number of moles.
Mass = Moles × molar mass of CuCl2
Mass = 0.008 mol × 134.45 g/mol
And there you have it! The mass of copper chloride dihydrate (CuCl2·2H2O) required to prepare 80.0 mL of a 0.10 M CuCl2 solution is approximately 1.076 grams.
Now, that wasn't too bad, was it? I hope I brought a smile to your face while doing those calculations!
To determine the mass of copper chloride dihydrate required, we will follow these steps:
Step 1: Find the molar mass of CuCl2·2H2O.
The molar mass of Cu is 63.55 g/mol, Cl is 35.45 g/mol, and H2O is 18.02 g/mol.
So, the molar mass of CuCl2·2H2O is:
(63.55 g/mol * 1) + (35.45 g/mol * 2) + (18.02 g/mol * 2) = 170.49 g/mol
Step 2: Convert the volume from milliliters to liters.
80.0 mL of CuCl2 solution is equal to 80.0 / 1000 = 0.080 L.
Step 3: Use the formula for molarity.
Molarity (M) is defined as moles of solute per liter of solution. Rearranging the formula gives us:
moles of solute = Molarity × volume (in liters)
In this case, the molarity is 0.10 M and the volume is 0.080 L.
So, the moles of CuCl2 required are:
0.10 M × 0.080 L = 0.008 mol
Step 4: Calculate the mass using the moles obtained.
To find the mass, multiply the moles of CuCl2 by the molar mass:
mass = moles × molar mass
mass = 0.008 mol × 170.49 g/mol
The mass of copper chloride dihydrate required to prepare the solution is:
mass = 1.364 g or approximately 1.36 g.