A cone is 3 inches high and has a base with a surface area of 7 square inches. What is the volume of the cone?

I thought the correct formula to use was 1/3(3.14)(r)^2(3), but not getting the correct answer. Please help.

The (3.14)(r)^2 part of the formula is the area of the base, and we know it is 7

so volume = (1/3)(7)(3) = 7 cubic inches

the volume of a cone = (1/3)(area of base)(height)

To calculate the volume of a cone, you need to use the formula V = (1/3)πr^2h, where V is the volume, π is pi (approximately 3.14), r is the radius of the base, and h is the height of the cone.

In this problem, you know the height of the cone is 3 inches, but you need to find the radius of the base. The given information is that the base has a surface area of 7 square inches. To find the radius, you can use the formula for the area of a circle:

A = πr^2

Since the surface area of the base is given as 7 square inches, you can set up the equation:

7 = πr^2

Now, solve for r by dividing both sides of the equation by π:

r^2 = 7/π

To find the radius, take the square root of both sides of the equation:

r = √(7/π)

Once you have the value of r, substitute it into the volume formula:

V = (1/3)π(√(7/π))^2(3)

Simplifying this further will give you the volume of the cone.