The area of a rectangle is 3/5 sqauare meter. The width is 2/5 meter.
How many times greater is the length than the width? Write your answer in simplest form
yuf
i still don't get it
To find the length of the rectangle, we need to divide the area by the width.
Step 1: Calculate the area of the rectangle
Given that the area of the rectangle is 3/5 square meter.
Area = 3/5 square meter
Step 2: Calculate the width of the rectangle
Given that the width is 2/5 meter.
Width = 2/5 meter
Step 3: Calculate the length
To find the length, we divide the area by the width.
Length = Area / Width = (3/5 square meter) / (2/5 meter)
When we divide two fractions, we can multiply the first fraction by the reciprocal of the second fraction.
Length = (3/5 square meter) * (5/2 meter)
= (3 * 5) / (5 * 2) square meter
= 15/10 square meter
= 3/2 square meter
So the length of the rectangle is 3/2 square meter.
Step 4: Compare the length and width
To find how many times greater the length is than the width, we need to divide the length by the width.
Length / Width = (3/2 square meter) / (2/5 meter)
To divide fractions, we multiply the first fraction by the reciprocal of the second fraction.
Length / Width = (3/2 square meter) * (5/2 meter)
= (3 * 5) / (2 * 2) square meter / meter
= 15/4 square meter/meter
= 15/4
Therefore, the length is 15/4 or 3.75 times greater than the width.
lw = area
l(2/5) = 3/5
multiply by 5
2l = 3
l = 3/2
length/width = (3/2) / (2/5) = (3/2)(5/2) = 15/4