Seawater contains approximately 3.5%NaCl by mass and has a density of 1.02 g/mL.

What volume of seawater contains 9.0 g of sodium?

mass of seawater= 9/.034=265grams

volume seawater=mass/density=265/1.02 ml

% Na in NaCl ... molar mass Na / molar mass NaCl

mass seawater needed ... (9.0 g / .035 NaCl/g) * %Na in NaCl

volume of seawater ... mass of seawater / density

To determine the volume of seawater that contains 9.0 g of sodium, we can use the following steps:

Step 1: Calculate the mass of sodium chloride (NaCl) in the seawater.
Given that seawater contains approximately 3.5% NaCl by mass, we can use the mass of seawater to find the mass of NaCl.
Mass of NaCl = 3.5/100 * mass of seawater

Step 2: Calculate the volume of seawater.
Given the density of seawater is 1.02 g/mL, we can use the density formula to find the volume of seawater.
Volume of seawater = Mass of seawater / Density of seawater

Step 3: Use the mass of NaCl to calculate the volume of seawater that contains 9.0 g of sodium.
Given that the atomic mass of sodium (Na) is 23 g/mol, we can use the following equation to find the volume of seawater containing 9.0 g of sodium:
Volume of seawater = (9.0 g / 23 g/mol) * (mass of seawater / mass of NaCl)

Let's calculate the volume of seawater containing 9.0 g of sodium:

Step 1: Mass of NaCl = 3.5/100 * mass of seawater

Step 2: Volume of seawater = Mass of seawater / Density of seawater

Step 3: Volume of seawater = (9.0 g / 23 g/mol) * (mass of seawater / mass of NaCl)

To determine the volume of seawater containing 9.0 g of sodium, we need to use the information given about the concentration of NaCl in seawater and the density of seawater.

1. First, let's calculate the mass of NaCl in the given volume of seawater.
Seawater contains approximately 3.5% NaCl by mass, which means that in 100 g of seawater, there are 3.5 g of NaCl.
So, if we know the mass of NaCl, we can calculate the mass of seawater using the percent composition.
In this case, we have 9.0 g of sodium, and since NaCl has a molar mass of approximately 58.5 g/mol, the mass of NaCl in 9.0 g of sodium is (9.0 g) / (58.5 g/mol) = 0.154 mol of NaCl.
To find the mass of seawater, we can set up a proportion: (0.154 mol NaCl) / (3.5 g NaCl) = (x g seawater) / (100 g seawater).
Solving for x, we get x ≈ 4.4 g.

2. Next, we need to determine the volume of seawater that has a mass of 4.4 g.
We know that the density of seawater is 1.02 g/mL, which means that 1 mL of seawater has a mass of 1.02 g.
Setting up a proportion: (4.4 g seawater) / (1.02 g/mL) = (y mL seawater) / (1 mL seawater).
Solving for y, we get y ≈ 4.31 mL.

Therefore, approximately 4.31 mL of seawater contains 9.0 g of sodium.