What volume, in milliliters, of a stock solution of 2.55 M NaOH would you have to use to prepare 1.00 L of a 0.500 M NaOH?
ml1 x M1 = mL2 x M2
Well, to answer your question, let's get a little "solution-oriented" here. The stock solution is 2.55 M, and you want to prepare a 0.500 M solution of NaOH. This means that the concentration needs to be diluted. How much? Well, it's like when you have a really strong cup of coffee and you want to make it milder. You add some water, right? Similarly, you need to dilute the stock solution of NaOH.
Now, let's do some calculations. The equation we can use for dilution is: C1V1 = C2V2, where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume. We know C1 is 2.55 M, C2 is 0.500 M, and V2 is 1.00 L. We need to find V1, the initial volume.
So, plugging in the numbers, we get: (2.55 M) * V1 = (0.500 M) * (1.00 L)
Now, let's solve for V1. Dividing both sides by 2.55 M, we get: V1 = (0.500 M * 1.00 L) / 2.55 M
Calculating that, we find V1 ≈ 0.196 L. But hold on a second! We want the volume in milliliters, not liters! Let's do a little extra math to convert that. Since 1 L is equal to 1000 mL, V1 in milliliters would be: 0.196 L * 1000 mL/L ≈ 196 mL.
So, you would need to use approximately 196 milliliters of the stock solution of 2.55 M NaOH to prepare 1.00 L of a 0.500 M NaOH solution. Just be careful not to spill any, because that might end up being a real "sodium-lly" situation.
To calculate the volume of the stock solution required, we can use the formula:
(V1)(C1) = (V2)(C2)
where:
V1 = volume of the stock solution (unknown)
C1 = concentration of the stock solution = 2.55 M
V2 = desired final volume = 1.00 L
C2 = desired final concentration = 0.500 M
Substituting the values into the formula, we get:
(V1)(2.55 M) = (1.00 L)(0.500 M)
V1 = (1.00 L)(0.500 M) / 2.55 M
V1 ≈ 0.196 L
Since the desired volume is requested in milliliters, we convert:
V1 = 0.196 L * (1000 mL / 1 L) ≈ 196 mL
Therefore, you would need to use approximately 196 mL of the stock solution to prepare 1.00 L of a 0.500 M NaOH solution.
To calculate the volume of the stock solution needed to prepare a desired concentration, you can use the formula:
C1V1 = C2V2
Where:
C1 = concentration of the stock solution (mol/L)
V1 = volume of the stock solution (L)
C2 = desired concentration (mol/L)
V2 = desired final volume (L)
In this case, you have the following information:
C1 = 2.55 M (stock solution concentration)
V1 = ?
C2 = 0.500 M (desired concentration)
V2 = 1.00 L (desired final volume)
Rearranging the formula, we have:
V1 = (C2 * V2) / C1
Plugging in the values, we get:
V1 = (0.500 M * 1.00 L) / 2.55 M
V1 = 0.196 L
To convert the volume from liters to milliliters, multiply by 1000:
V1 = 0.196 L * 1000 mL/L
V1 = 196 mL
Therefore, you would have to use 196 mL of the 2.55 M NaOH stock solution to prepare 1.00 L of a 0.500 M NaOH solution.