Each page of a top-secret report on aliens requires 2 KB of space in digital format.
What is the maximum number of pages the report can have so that it can be completely stored on a USB drive that holds 4*10^6
Write your answer in scientific notation, and round to one decimal place.
Wrong, but thanks!
I found out it was 2 * 10^6
2x10^6
To find the maximum number of pages the report can have, we need to divide the total storage capacity of the USB drive by the space required for each page.
Given:
Space required for each page = 2 KB = 2 * 10^3 bytes
USB drive capacity = 4 * 10^6 bytes
To convert the USB drive capacity into kilobytes, we divide it by 10^3:
4 * 10^6 bytes / 10^3 = 4 * 10^3 KB
Now, we can calculate the maximum number of pages:
Maximum number of pages = USB drive capacity / Space required for each page
= 4 * 10^3 KB / 2 * 10^3 bytes
= (4 / 2) * 10^3 KB / 10^3 bytes
= 2 KB / 1 byte
The number of bytes cancels out, leaving us with:
Maximum number of pages = 2
Therefore, the maximum number of pages the report can have so that it can be completely stored on the USB drive is 2.
In scientific notation, this can be written as:
2 * 10^0 pages
Rounded to one decimal place, the answer is:
2.0 pages.
n * 2*10^3 = 4 * 10^6
n = (4/2)(10^6/10^3) = 2 * 10^(6-3) = 2.0 * 10^3