A helicopter has a mass of 4280kg. The helicopter is lifted off the ground with a vertically upward acceleration of 2.030m/s^2. Calculate the vertical force exerted on the rotating blades of the helicopter by the air under the blades.
F up - weight down = m a up
F - 4280*9.81 = 4280 *2.030
To calculate the vertical force exerted on the rotating blades of the helicopter by the air under the blades, we need to use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
In this scenario, the force we want to find is the vertical force exerted on the blades, the mass of the helicopter is given as 4280 kg, and the vertically upward acceleration is given as 2.030 m/s^2.
Using Newton's second law, we can calculate the force:
Force = Mass × Acceleration
Force = 4280 kg × 2.030 m/s^2
Force = 8688.4 N
Therefore, the vertical force exerted on the rotating blades of the helicopter by the air under the blades is 8688.4 Newtons.