If v=3i+4j+5k is the instantaneous velocity of a body mass 1.5kg. Calculate it's kinetic en
ergy.c choose the correct one
a)37.5joules
b)47.5joules
c)57.5joules
d)none
KE = 1/2 mv^2
|v|^2 = 3^2+4^2+5^2 = 50
1/2 * 1.5 * 50 = 37.5
V= 3i+ 4j + 5k indtaneous velocity mass 1.50 kilograms calculate its ke
37.5
a)37.5joules
Thanks 😊 you
To calculate the kinetic energy of an object, we need to use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given:
Mass (m) = 1.5 kg
Velocity (v) = 3i + 4j + 5k
Let's calculate the velocity squared first:
Magnitude of Velocity^2 = (3i + 4j + 5k) * (3i + 4j + 5k)
= (9i^2 + 16j^2 + 25k^2) + (24ij + 30ik + 40jk)
= 9 + 16 + 25 + 24ij + 30ik + 40jk
= 50 + 24ij + 30ik + 40jk
The scalar part of the vector (50) is what we need for the velocity squared. Now we can calculate the kinetic energy:
Kinetic Energy = (1/2) * mass * (Magnitude of Velocity^2)
= (1/2) * 1.5 * 50
= 0.75 * 50
= 37.5 joules
Therefore, the correct answer is option a) 37.5 joules.