How can you balance this equation?
C(2)H(6) + O(2) ---> CO(2) + H(2)O
The answer is 2C2H6 + 7O2 ———- 4CO2 + 6H20.
"most important thing about balancing equations is balancing the odd atoms first such as carbon, C in this case
balance 2 C on right because there’s already 2 C on left
this gives CO2 -> 2C02
next u balance hydrogen, H on the right because there is 6 on the left by H2O -> 3H2O
always balance oxygen O the last/last few because it can be easily balanced due to the O2 on the right, O2 -> 5/2O2
overall equation would look like,
C2H6 + 5/2O2 -> 2CO2 + 3H2O
in order to remove the fraction, multiply the entire equation by 2
C2H6 + 5/2O2 -> 2CO2 + 3H2O x2"
Quoted from Sim Seemin on Quora.
To balance the equation C(2)H(6) + O(2) → CO(2) + H(2)O, we need to make sure that the number of atoms of each element on both sides of the equation is equal.
Here's how you can balance this equation step-by-step:
1. Start by balancing the carbon atoms on both sides of the equation. There are 2 carbon atoms on the left side (C2H6) and 1 carbon atom on the right side (CO2). To balance this, put a coefficient of 2 in front of CO2:
C2H6 + O2 → 2CO2 + H2O
2. Now, let's balance the hydrogen atoms. There are 6 hydrogen atoms on the left side (C2H6) and 2 hydrogen atoms on the right side (H2O). To balance this, put a coefficient of 3 in front of H2O:
C2H6 + O2 → 2CO2 + 3H2O
3. Finally, let's balance the oxygen atoms. There are 2 oxygen atoms on the left side (O2) and 4 oxygen atoms on the right side (2CO2 + 3H2O). To balance this, adjust the coefficient in front of O2:
C2H6 + 3.5O2 → 2CO2 + 3H2O
Since we can't have fractional coefficients, we multiply the entire equation by 2 to eliminate the 3.5 coefficient:
2C2H6 + 7O2 → 4CO2 + 6H2O
Now the equation is balanced.
To balance the given chemical equation, follow these steps:
Step 1: Count the number of atoms for each element on both sides of the equation.
On the left side:
C (carbon): 2
H (hydrogen): 6
On the right side:
C (carbon): 1
H (hydrogen): 2
O (oxygen): 3
Step 2: Balance the carbon atoms:
Currently, there are 2 carbon atoms on the left side and 1 carbon atom on the right side. To balance carbon, put a coefficient of 2 in front of CO2 on the right side:
C2H6 + O2 ---> 2CO2 + H2O
Step 3: Balance the hydrogen atoms:
Currently, there are 6 hydrogen atoms on the left side and 2 hydrogen atoms on the right side. To balance hydrogen, put a coefficient of 3 in front of H2O on the right side:
C2H6 + O2 ---> 2CO2 + 3H2O
Step 4: Balance the oxygen atoms:
Currently, there are 2 oxygen atoms on the left side and 7 oxygen atoms on the right side. To balance oxygen, put a coefficient of 7/2 (or 3.5) in front of O2 on the left side:
C2H6 + (7/2)O2 ---> 2CO2 + 3H2O
However, it is best to work with whole numbers. To convert the coefficient of O2 to a whole number, multiply all coefficients by 2:
2C2H6 + 7O2 ---> 4CO2 + 6H2O
Now the equation is balanced with 2 carbon atoms, 6 hydrogen atoms, and 14 oxygen atoms on both sides.