Calculate the volume of carbon 4 oxide gas at s.t.p when 5g of zinc trioxocarbonate is heated strongly.
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To calculate the volume of carbon 4 oxide gas (also known as carbon monoxide) at standard temperature and pressure (STP) when 5g of zinc trioxocarbonate is heated strongly, we need to follow these steps:
Step 1: Determine the molar mass of zinc trioxocarbonate (ZnCO₃).
According to the periodic table, the atomic masses of zinc (Zn), carbon (C), and oxygen (O) are approximately 65.38 g/mol, 12.01 g/mol, and 16.00 g/mol, respectively.
The molar mass of zinc trioxocarbonate can be calculated as follows:
Molar mass of ZnCO₃ = (Atomic mass of Zn) + (Atomic mass of C) + (3 × Atomic mass of O)
Molar mass of ZnCO₃ = (65.38 g/mol) + (12.01 g/mol) + (3 × 16.00 g/mol)
Molar mass of ZnCO₃ ≈ 125.4 g/mol
Step 2: Convert the given mass of zinc trioxocarbonate to moles.
Using the equation:
Moles = Mass / Molar mass
Moles of ZnCO₃ = 5g / 125.4 g/mol
Moles of ZnCO₃ ≈ 0.04 mol
Step 3: Determine the stoichiometry of the reaction.
By looking at the chemical equation involved in the decomposition of zinc trioxocarbonate,
ZnCO₃ -> ZnO + CO₂
We can see that for every 1 mole of zinc trioxocarbonate, 1 mole of carbon monoxide (CO) gas is produced.
Step 4: Calculate the volume of carbon monoxide gas at STP.
At STP, 1 mole of any gas occupies 22.4 liters of volume.
Therefore, the volume of carbon monoxide gas can be calculated as follows:
Volume of CO gas = Moles of CO × 22.4 L/mol
Volume of CO gas = 0.04 mol × 22.4 L/mol
Volume of CO gas ≈ 0.896 L
So, the volume of carbon monoxide gas at STP, when 5g of zinc trioxocarbonate is heated strongly, is approximately 0.896 liters.