help me please I do understand I got the wrong answer:

Solve the following system of linear equations by graphing
4x-2y=8 and x-y=0
1. 4x-2y=8
-2y/-2=4x/-2+8/-2
y=-2x/1-4 (0,-4)

2. x-y=0
-y/-1=x/-1+0/-1
y=1/-1+0 (0,0)

4x-2y=8 and x-y=0

well first of all you see immediately that y = x
so 2 x = 8 and x = 4 so y = 4
BUT you are supposed to do y = m x + b'
1. 4x-2y=8
-2y = -4x + 8
y = 2 x - 4 slope = 2 through (0, -4)

2. x-y=0
-y = - x
y = 1x + 0 slope = 1 through origin

how would you graph it?

To solve the system of linear equations by graphing, you need to plot the equations on a graph and find their intersection point. The point of intersection represents the solution of the system.

Let's start by graphing the first equation, which is 4x-2y=8. To do this, rearrange the equation in the form y = mx + b, where m is the slope and b is the y-intercept.

4x - 2y = 8
-2y = -4x + 8
y = 2x - 4/2
y = 2x - 2

Now, choose a range of x values to plot on the graph. Let's say -5 to 5. Substitute different x values into the equation to find corresponding y values.

When x = 0,
y = 2(0) - 2
y = -2
So, one point on the graph is (0, -2).

When x = 1,
y = 2(1) - 2
y = 2
Another point on the graph is (1, 2).

Plot these points on the graph and connect them with a straight line. This line represents the first equation.

Next, let's graph the second equation, x - y = 0. Again, rearrange the equation in y = mx + b form.

x - y = 0
y = x

Using the same range of x values (-5 to 5), substitute different x values into the equation to find corresponding y values.

When x = 0,
y = 0
So, one point on the graph is (0, 0).

When x = 1,
y = 1
Another point on the graph is (1, 1).

Plot these points on the graph and connect them with a straight line. This line represents the second equation.

Now look for the point where the two lines intersect. This point represents the solution to the system of equations. In this case, it appears that the two lines intersect at (1, 1), which means x = 1 and y = 1.

To verify this solution, substitute the values of x and y into both equations.

For the first equation:
4x - 2y = 8
4(1) - 2(1) = 8
4 - 2 = 8
2 = 8 (This is false.)

For the second equation:
x - y = 0
1 - 1 = 0
0 = 0 (This is true.)

Since the solution satisfies the second equation but not the first, the given system of equations has no solution.

I hope this explanation helps you understand the process of solving a system of linear equations by graphing.