Scientists want to place a 3100 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 1.9 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:
mmars = 6.4191 x 1023 kg
rmars = 3.397 x 106 m
G = 6.67428 x 10-11 N-m2/kg2
1) What is the force of attraction between Mars and the satellite?
I got 1600 but that's wrong
G * mmars * 3.1E3 / (2.9 * rmars)
I think you should square the denominator
To find the force of attraction between Mars and the satellite, we can use the formula for gravitational force:
F = G * ((m1 * m2) / r^2)
Where:
F is the force of attraction between the two objects
G is the universal gravitational constant (6.67428 x 10^-11 N-m^2/kg^2)
m1 and m2 are the masses of the two objects (in this case, the satellite and Mars)
r is the distance between the two objects (in this case, the distance between the center of Mars and the satellite)
In this case, the mass of the satellite (m2) is given as 3100 kg, and the mass of Mars (m1) is given as 6.4191 x 10^23 kg. The distance (r) is given as 1.9 times the radius of Mars, which is 1.9 * 3.397 x 10^6 m.
Let's substitute these values into the formula:
F = (6.67428 x 10^-11 N-m^2/kg^2) * ((3100 kg * 6.4191 x 10^23 kg) / (1.9 * 3.397 x 10^6 m)^2)
Calculating this expression will give us the force of attraction between Mars and the satellite.