120g of sodium hydroxide pellets dissolve in 800cm3 of its solution. Determine the mass concentration of the solution

As weight/volume (w/v) the concentration is

120 g NaOH/800 cc = ? g/cc.

As weight/eight (w/w) and assuming the density of water as 1.00 g/cc, then the mass of the 800 cc H2O is 800 grams + 120 g NaOH = 929 grams total weight so concentration is 120 g NaOH/920 g solution = ? g NaOH/gram solution.

To determine the mass concentration of the solution, we need to divide the mass of the solute (sodium hydroxide) by the volume of the solution.

Given:
Mass of sodium hydroxide pellets = 120g
Volume of the solution = 800cm³

Step 1: Convert the volume from cm³ to liters (L)
1 L = 1000 cm³
Therefore, 800 cm³ = 800/1000 = 0.8 L

Step 2: Divide the mass of the solute by the volume of the solution
Mass concentration = Mass of solute / Volume of solution

Mass concentration = 120g / 0.8 L
Mass concentration = 150 g/L

Therefore, the mass concentration of the sodium hydroxide solution is 150 g/L.

To determine the mass concentration of a solution, we need to calculate the mass of solute (sodium hydroxide) divided by the volume of the solution. The mass concentration is typically expressed in terms of grams per liter (g/L).

First, we need to convert the volume from cm³ to liters. Since 1 liter (L) is equal to 1000 cm³, we divide the given volume of 800 cm³ by 1000 to get 0.8 L.

Next, we calculate the mass of sodium hydroxide dissolved in the solution. We are given that 120 g of sodium hydroxide pellets dissolve, so the mass of solute is 120 g.

Now, we are ready to calculate the mass concentration. We divide the mass of solute (120 g) by the volume of the solution (0.8 L):

Mass concentration = Mass of solute / Volume of solution
= 120 g / 0.8 L
= 150 g/L

Therefore, the mass concentration of the sodium hydroxide solution is 150 g/L.