A nursery sells Kentucky Blue Grass seed for $5.75 per pound and Tall Fescue seed for$4.50 per pound. The nursery sells a mixture of the two kinds of seed for$5.25 per pound. Let k represent the amount of Kentucky Blue Grass seed the nursery uses in 5 pounds of the mixture. Write an equation to represent the problem. How much Kentucky Blue Grass does the nursery use in 5 pounds of the mixture? How much Tall Fescue does the nursery use in 5 pounds of the mixture?
see the coffee example, and the lima bean example.
http://www.purplemath.com/modules/mixture.htm
i still don't get it
is the equation k=m-TF
Yes, you are correct. The equation to represent the problem is k = m - TF, where k represents the amount of Kentucky Blue Grass seed used in 5 pounds of the mixture, m represents the total weight of the mixture in pounds, and TF represents the amount of Tall Fescue seed used in 5 pounds of the mixture.
To find the amount of Kentucky Blue Grass seed used in 5 pounds of the mixture, we can substitute the given values into the equation.
Given:
Price of Kentucky Blue Grass seed = $5.75 per pound
Price of Tall Fescue seed = $4.50 per pound
Price of the mixture = $5.25 per pound
Let's assume that the total weight of the mixture is 5 pounds (m = 5).
Substitute this value into the equation: k = m - TF
k = 5 - TF
To find the amount of Kentucky Blue Grass seed used, we need to solve for k. We know that the price of the mixture is $5.25 per pound, so we can set up an equation based on the prices of the two seed types in the mixture:
5.75k + 4.50TF = 5.25(5)
Now, we can solve this equation to find the value of k.
To find the amount of Tall Fescue seed used in 5 pounds of the mixture, we can substitute the value of k into the equation.