Given line AB, explain how to construct a square with sides of length AB.

yall get the answer yet?

To construct a square with sides of length AB, follow these steps:

1. Start by drawing line segment AB. This will serve as one side of the square.

2. Using a compass, place the center at point A or B and adjust the radius to the length of AB. This will create a circle with AB as its diameter.

3. Without changing the compass radius, draw an arc from point A that intersects the circle at two points (let's call them C and D). Similarly, draw an arc from point B that intersects the circle at two points (E and F).

4. Using a straightedge, draw the line segments AC, AB, and BC, forming an isosceles triangle.

5. Now, using the compass, place the center at point C and adjust the radius to the length of AC. Draw an arc that intersects line segment BC and the extended line segment BC produced at point G.

6. Finally, using a straightedge, draw line segment CG. This completes the construction of square ABCD, with all sides having a length equal to AB.

Remember, when constructing any geometric shape, precision and accuracy are essential. Ensure that your compass, straightedge, and markings are precise to achieve an accurate square.

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