A box contains 7 pieces of candy: 1 green, 1 blue, and 5 red. You select one piece at random. Find the following probabilities:
a.) P(green or red ) = 5/7-1/7=4/7
b.) P(green and red ) =6/7
c.) P (green or blue ) = 1/7-1/7=7
d.) P(not(green or blue) ) =1-1/7-1/7=5/7
a.) how many pieces are either red or green?
b.) selecting ONE piece , how do you get green AND red?
c.) how many pieces are either blue or green?
d.) how many pieces are neither blue nor green?
Why did you repeat the question when it was answered already?
https://www.jiskha.com/questions/1774967/A-box-contains-7-pieces-of-candy-1-green-1-blue-and-5-red-You-select-one-piece
I had asked you to do the other parts in the same way, but you decided not to, and simply repeated the same question hoping somebody would do the work for you.
To find the probabilities, we need to calculate the number of favorable outcomes and divide it by the total number of possible outcomes.
a.) P(green or red) = P(green) + P(red) = 1/7 + 5/7 = 6/7
b.) P(green and red) = 0 (since it's not possible to select both green and red candies in this scenario)
c.) P(green or blue) = P(green) + P(blue) = 1/7 + 1/7 = 2/7
d.) P(not(green or blue)) = 1 - P(green or blue) = 1 - 2/7 = 5/7
Let's break down the question and look at each part:
a) P(green or red) refers to the probability of selecting either a green or red candy from the box. In this case, we have 5 red candies out of a total of 7 candies, so the probability of selecting a red candy is 5/7. Since there is only 1 green candy, the probability of selecting a green candy is 1/7. To find the probability of selecting either a green or red candy, we add the probabilities together: 1/7 + 5/7 = 6/7.
b) P(green and red) refers to the probability of selecting both a green and red candy from the box. However, since there is only 1 green candy and 5 red candies, it is not possible to select both a green and red candy at the same time. Therefore, the probability of this event occurring is 0.
c) P(green or blue) refers to the probability of selecting either a green or blue candy from the box. In this case, there is only 1 green candy and 1 blue candy, so the total number of candies that are green or blue is 2. The total number of candies in the box is still 7. Therefore, the probability of this event occurring is 2/7.
d) P(not(green or blue)) refers to the probability of not selecting either a green or blue candy from the box. To find this, we need to calculate the probability of selecting a candy that is neither green nor blue. Since there are 5 red candies out of a total of 7 candies, the probability of selecting a red candy is 5/7. This represents the probability of not selecting either a green or blue candy. Therefore, the probability of not selecting either a green or blue candy is 5/7.