b(b^2+1)+2(b^2+1)
distribute and add like terms
b^3 + b + 2 b^2 + 2
arrange in descending order
i need to factor the polynomial as the product of two binomials
b(b^2+1)+2(b^2+1)
you should see the common factor of (b^2 + 1)
= (b^2 + 1)(b + 2)
To simplify the expression b(b^2 + 1) + 2(b^2 + 1), you can use the distributive property.
Step 1: Distribute b to the terms inside the first parentheses:
b(b^2 + 1) = b * b^2 + b * 1 = b^3 + b
Step 2: Distribute 2 to the terms inside the second parentheses:
2(b^2 + 1) = 2 * b^2 + 2 * 1 = 2b^2 + 2
Now, we have:
b(b^2 + 1) + 2(b^2 + 1) = (b^3 + b) + (2b^2 + 2)
To simplify further, we can combine like terms:
(b^3 + 2b^2) + (b + 2)
Finally, the simplified expression is:
b^3 + 2b^2 + b + 2