How many mililiters of water would be displaced by 408 grams of lead?
There are 0.789 grams in a milliliter. You can figure it out from there.
ILTHSM ... in a milliliter of what?
density of water is one gram per mL ... usually written as ... 1 g/cm^3
density of lead is ... 11.3 g/cm^3
water displaced is ... (408 g) / (11.3 g/cm^3)
Wait josh? Do you go to Connections Academy or K12?
To find out how many milliliters of water would be displaced by 408 grams of lead, we need to consider the density of lead and use the formula for displacement.
The density of lead is 11.34 grams per milliliter (g/mL). This means that each milliliter of lead has a mass of 11.34 grams.
To find the volume of lead we can use the formula:
Volume (V) = Mass (M) / Density (D)
In this case, the mass of lead (M) is 408 grams and the density of lead (D) is 11.34 g/mL.
Plugging these values into the formula, we get:
V = 408 g / 11.34 g/mL
Simplifying the equation, we find:
V ≈ 35.98 mL
Therefore, 408 grams of lead would displace approximately 35.98 milliliters of water.