i was wondering what the balance equation this would be
NaOH + H3PO4 --> Na3PO4 + H-OH (H20)
thank you
To balance the given chemical equation:
NaOH + H3PO4 → Na3PO4 + H-OH (H2O)
Step 1: Count the number of atoms on each side of the equation.
On the left side:
- Sodium (Na): 1
- Oxygen (O): 1
- Hydrogen (H): 4
- Phosphorus (P): 1
On the right side:
- Sodium (Na): 3
- Oxygen (O): 5
- Hydrogen (H): 1
- Phosphorus (P): 1
Step 2: Start by balancing the atoms that appear in only one compound on each side of the equation.
We can start by balancing sodium (Na) by placing a coefficient of 3 in front of NaOH on the left side:
3 NaOH + H3PO4 → Na3PO4 + H-OH (H2O)
Now the number of sodium atoms is balanced.
Step 3: Next, balance phosphorus (P). Add a coefficient of 3 in front of H3PO4 on the left side:
3 NaOH + 3 H3PO4 → Na3PO4 + H-OH (H2O)
Now the number of phosphorus atoms is balanced.
Step 4: Balance hydrogen (H). Add a coefficient of 6 in front of H-OH on the right side:
3 NaOH + 3 H3PO4 → Na3PO4 + 6 H-OH (H2O)
Now the number of hydrogen atoms is balanced.
Step 5: Finally, balance oxygen (O). Add a coefficient of 6 in front of H2O on the right side:
3 NaOH + 3 H3PO4 → Na3PO4 + 6 H-OH + 6 H2O
Now the number of oxygen atoms is balanced.
The balanced equation is:
3 NaOH + 3 H3PO4 → Na3PO4 + 6 H-OH + 6 H2O