A 72kg cement block rides a crane to reach the upper floor of the building. What force does the bucket of the lift exert on the surgeon when the bucket is moving upward at a steady 2.3 m/s?
I don't have an acceleration so what do i do?
you do have acceleration, it is zero. What does steady velocity mean?
To solve this problem, you need to use Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration. In this case, since you don't have the acceleration, you can assume that the bucket is moving upward at a steady speed of 2.3 m/s, which means that the acceleration is zero.
Since the acceleration is zero, according to Newton's second law, the net force on the cement block is also zero. This means that the force exerted by the bucket on the cement block is equal in magnitude and opposite in direction to the force exerted by the cement block on the bucket.
To find the force exerted by the bucket on the surgeon, you can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. Therefore, the force exerted by the bucket on the surgeon will be equal in magnitude and opposite in direction to the force exerted by the surgeon on the bucket.
Since the force exerted by the surgeon on the bucket is equal to the weight of the cement block (mg), where m is the mass of the cement block and g is the acceleration due to gravity (approximately 9.8 m/s^2), the force exerted by the bucket on the surgeon will also be equal to the weight of the cement block.
Therefore, the force exerted by the bucket on the surgeon in this scenario will be equal to the weight of the cement block, which can be calculated as:
Force = mass * acceleration due to gravity
= 72 kg * 9.8 m/s^2
= 705.6 N
So, the force exerted by the bucket of the lift on the surgeon when the bucket is moving upward at a steady 2.3 m/s is 705.6 Newtons.