Right now we are learning about graphing inequalities. This is hard to explain without showing you the graph, but:

Find the inequality graphed below.

Obviously, I can't show you the picture, but what I figured out that the slope was up 1, over 1/3, etc.

How would I write that into an inequality, preferably in standard form.

Thanks!

The y above will be y>1x+1/3, The y below will be y<1x+1/3

I am not certain of the sign of the 1/3 from your description.

What do you mean by the sign?

To write the inequality represented by a given graph, you need to consider the slope of the line and the boundary point(s) on the line.

Let's analyze your description: "the slope was up 1, over 1/3, etc." This means that for every 1 unit increase in the vertical direction (up), there is a 1/3 unit increase in the horizontal direction (over). This information gives us the slope of the line.

Now, let's consider the boundary point(s) on the line. Since you haven't provided any specific points on the line, I'll assume that the line passes through the origin (0,0).

To write the inequality in standard form, we can use the slope-intercept form of a linear equation (y = mx + b), where m represents the slope and b represents the y-intercept. Since the line passes through the origin, the y-intercept is 0.

The slope you mentioned, up 1 and over 1/3, can be represented as 1/3. So, the equation of the line becomes y = (1/3)x + 0, which simplifies to y = (1/3)x.

To convert this equation into standard form (Ax + By = C), we multiply both sides by 3 to eliminate the fraction:

3y = x.

By rearranging the terms and moving them to the left side of the equation:

x - 3y = 0.

Thus, the inequality corresponding to this line, in standard form, is:

x - 3y ≥ 0.