A truck travels up a hill. With a 6.5 incline the truck has a constant speed of 17 m/s what is the horizontal component of the trucks velocity
6.5 degrees?
Vh = 17 m/s * cos(6.5º)
To find the horizontal component of the truck's velocity, we need to calculate the magnitude of the velocity vector in the horizontal direction.
First, let's define the given information:
- Inclination of the hill (angle) = 6.5 degrees
- Speed of the truck (magnitude of velocity) = 17 m/s
To find the horizontal component, we can use trigonometry. The horizontal component of the velocity can be found by multiplying the magnitude of the velocity (17 m/s) by the cosine of the incline angle (6.5 degrees).
Horizontal component = Magnitude of velocity * cos(angle)
Now let's plug in the values and calculate:
Horizontal component = 17 m/s * cos(6.5 degrees)
Using a scientific calculator, we find:
Horizontal component ≈ 16.944 m/s
So, the horizontal component of the truck's velocity is approximately 16.944 m/s.