A town clock has the minute hand that is 1.5 m long and an hour and that is 1.2 m long what is the approximate distance in meters between the ends of the hand at 9 o’clock/////plz help

2.3

1.9
0.9
0.3

at 9 o'clock the hands form a right angle

the distance between the ends is the hypotenuse of a right triangle

by Pythagoras ... d^2 = 1.5^2 + 1.2^2

Wait.....so, what's the answer?

What’s the answer

its 1.9

4.6.5 connexus answers!!

1) C. 22
2) A. 127
3) B. 1.9
4) B. 20
5) B. 33, 44, 55
yw bby!!

To find the distance between the ends of the hour and minute hands at 9 o'clock, we need to determine the positions of both hands.

First, let's find the position of the minute hand at 9 o'clock. Since the minute hand represents the minutes and is 1.5m long, it will be pointing directly at the 9-minute mark on the clock face.

Next, let's determine the position of the hour hand at 9 o'clock. Since the hour hand represents the hours, it will be pointing directly at the 9-hour mark on the clock face. However, the hour hand also considers the fraction of the hour that has passed. At 9 o'clock, the hour hand would have moved 1/4th of the way between the 9 and 10-hour mark because 9 o'clock is a quarter (1/4th) into the hour.

Now, visualize the clock face. The distance between the ends of the hands is the straight-line distance between the positions of the minute and hour hand.

To calculate this distance, we can use the Pythagorean theorem, which states that the square of the hypotenuse (longest side) of a right-angled triangle is equal to the sum of the squares of the other two sides.

In our case, the distance between the ends of the hands forms the hypotenuse of a right-angled triangle, with the hour hand as one side and the minute hand as the other side.

Using the Pythagorean theorem, we can calculate the distance between the ends of the hands as follows:

Distance^2 = (Length of the hour hand)^2 + (Length of the minute hand)^2

Distance^2 = (1.2m)^2 + (1.5m)^2

Distance^2 = 1.44m^2 + 2.25m^2

Distance^2 = 3.69m^2

Taking the square root of both sides, we find:

Distance ≈ √3.69 ≈ 1.92 meters

Therefore, the approximate distance between the ends of the hour and minute hands at 9 o'clock is approximately 1.92 meters.