A fictitious element X is composed of 70.0 percent of the isotope X^45, 20.0 percent of the isotope X^ 46, and 10.0 percent of the isotope X^47. Calculate the weighted atomic mass of element X to the nearest tenth. pls show all work
(0.70 * 45) + (0.20 * 46) + (0.10 * 47)
thank you!!!
To calculate the weighted atomic mass of element X, we need to multiply the percent abundance of each isotope by its atomic mass, and then sum up the results.
1. Determine the atomic masses of the isotopes:
- The isotope X^45 has an atomic mass of 45.0 amu.
- The isotope X^46 has an atomic mass of 46.0 amu.
- The isotope X^47 has an atomic mass of 47.0 amu.
2. Calculate the weighted atomic mass:
- Multiply the percent abundance of each isotope by its atomic mass.
- Sum up the results.
Let's perform the calculations:
Weighted atomic mass = (percent abundance of X^45 * atomic mass of X^45) + (percent abundance of X^46 * atomic mass of X^46) + (percent abundance of X^47 * atomic mass of X^47)
Weighted atomic mass = (70.0% * 45.0 amu) + (20.0% * 46.0 amu) + (10.0% * 47.0 amu)
Weighted atomic mass = (0.70 * 45.0 amu) + (0.20 * 46.0 amu) + (0.10 * 47.0 amu)
Weighted atomic mass = 31.5 amu + 9.2 amu + 4.7 amu
Weighted atomic mass = 45.4 amu
Therefore, the weighted atomic mass of element X is approximately 45.4 amu (rounded to the nearest tenth).