A hockey puck is observed to be sliding along a flat frictionless surface at a speed of 42 mm/s. There is no net force acting on the puck. Assuming it doesn't smash into anything, how FAST will the puck be going 2 h later?
Vo = 0.042 m/s.
a = 0.
t = 2 h = 7200 s.
V = Vo + a*t = 0.042 + 0*7200 =
To determine how fast the puck will be moving 2 hours later, we need to consider the concept of inertia. Inertia is the tendency of an object to resist a change in its state of motion. Since there is no net force acting on the hockey puck, it will continue moving with a constant velocity over time.
Given that the puck is sliding with a speed of 42 mm/s initially and assuming no external forces act on it, we can conclude that its speed will remain constant throughout.
To find the speed of the puck 2 hours later, we need to convert the time from hours to seconds. There are 60 minutes in an hour, and 60 seconds in a minute. Therefore, 2 hours can be converted to:
2 hours = 2 × 60 minutes = 2 × 60 × 60 seconds = 7,200 seconds
Since the speed of the puck remains constant, we can conclude that the speed of 42 mm/s will be maintained for the entire 2-hour period. Therefore, 2 hours later, the puck will still be moving at a speed of 42 mm/s.