Balance this equation
2Cd(No3)2 + (NH2)2S-2CdS +2NH4No3
can not
2*m*Cd(No3)2 + n* (NH2)2S -------> 2*k*CdS +2*j*NH4No3 maybe?
Cd 2m = 2k
so
k = m
2*m*Cd(No3)2 + n* (NH2)2S -------> 2*m*CdS +2*j*NH4No3
S 2n = 2m
so n = m
2*m*Cd(No3)2 + m* (NH2)2S -------> 2*m*CdS +2*j*NH4No3
N 4m +2m = 4 j
so j = 3m/2
2*m*Cd(No3)2 + m* (NH2)2S -------> 2*m*CdS + 3*m*NH4No3
2 Cd(No3)2 + (NH2)2S -------> 2 CdS + 3 NH4No3
check
O 12 = 9 nope
This is what you wrote:
2Cd(No3)2 + (NH2)2S-2CdS +2NH4No3
Probably this is what you meant:
Cd(NO3)2 + (NH4)2S ==> CdS + NH4NO3
It is balanced this way.
Cd(NO3)2 + (NH4)2S ==> CdS + 2NH4NO3
To balance the chemical equation, follow these steps:
Step 1: Count the number of atoms of each element on the reactant (left) side and the product (right) side.
Reactants:
- 2 Cd (cadmium)
- 4 N (nitrogen)
- 12 O (oxygen)
- 8 H (hydrogen)
- 2 S (sulfur)
Products:
- 2 Cd (cadmium)
- 1 N (nitrogen)
- 16 O (oxygen)
- 8 H (hydrogen)
- 2 S (sulfur)
Step 2: Determine the elements that are not balanced. In this case, the nitrogen (N) and oxygen (O) are unbalanced as they have different quantities on each side.
Step 3: Start balancing with the elements appearing in the fewest compounds. In this case, we start by balancing nitrogen (N).
Balancing Nitrogen (N)
- On the reactant side, there are 4 N atoms (2 in Cd(NO3)2 and 2 in NH4NO3)
- On the product side, there is only 1 N atom in CdS
To balance the N atoms, multiply the compound NH4NO3 by 4:
2 Cd(NO3)2 + 4(NH4NO3) → (NH2)2S + 2 CdS + 8 NH4NO3
Step 4: Balancing Oxygen (O)
- On the reactant side, there are 12 O atoms (6 in Cd(NO3)2 and 6 in NH4NO3)
- On the product side, there are 16 O atoms (8 in NH4NO3 and 8 in CdS)
To balance the O atoms, multiply the compound Cd(NO3)2 by 4 and NH4NO3 by 2:
8 Cd(NO3)2 + 4(NH4NO3) → (NH2)2S + 8 CdS + 8 NH4NO3
Step 5: Finally, balance the remaining elements. In this case, Cd (cadmium) and S (sulfur) are already balanced, and H (hydrogen) is balanced through the multiplication in Step 3.
Therefore, the balanced equation is:
8 Cd(NO3)2 + 4(NH4NO3) → (NH2)2S + 8 CdS + 8 NH4NO3