(7z^ m )(nz ^ 3 )=−14z
7z^m * nz^3 = -14z
7nz^(m+3) = -14z
z^(m+2) = -2
z needs to be negative, and m needs to be odd
I suspect the problem had a typo or two.
take a look what Scott and Damon did here:
https://www.jiskha.com/questions/1772305/7z-m-nz-3-14z-7-solve-for-m-and-n
It was posted as: (7z^m)(nz^3)=-14z^7 , solve for m and n
Are they supposed to be the same problem ?
what m and n
To solve the equation (7z^m)(nz^3) = -14z, we need to simplify the left side of the equation.
First, we can multiply the coefficients 7n and -14 to get -98:
-98z^m * z^3 = -14z
Next, we apply the product rule of exponents by adding the exponents:
-98z^(m+3) = -14z
Now, we can equate the corresponding coefficients on both sides:
-98 = -14
Since -98 is not equal to -14, the equation has no solution.
Therefore, there is no value for z that will satisfy the given equation (-98z^(m+3) = -14z).